20n^2+46n+24=0

Solution for 20n^2+46n+24=0 equation:

20n^2+46n+24=0

a = 20; b = 46; c = +24;
Δ = b2-4ac
Δ = 462-4·20·24
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-14}{2*20}=\frac{-60}{40}
=-1+1/2
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+14}{2*20}=\frac{-32}{40}
=-4/5
$